发布于2022-11-13 16:16 阅读(1077) 评论(0) 点赞(8) 收藏(1)
我正在创建一个代表变形虫进化的模拟。它们由在画布上移动的红色方块表示。如果它们发生碰撞,它们就会产生后代。进化带有一个称为成熟速度的数量。变形虫只有在达到一定年龄后才能繁殖,而它们年龄增长的速度取决于它们的成熟速度,这会遗传给后代(有一些随机突变的机会)。这是我的代码:
import pygame
import random
import time
import itertools
from pygame.locals import (
QUIT
)
pygame.init()
SCREEN_WIDTH = 500
SCREEN_HEIGHT = 500
screen = pygame.display.set_mode([500, 500])
amoebas = pygame.sprite.Group()
all_sprites = pygame.sprite.Group()
idList = []
mutationConstant = 100
class Amoeba(pygame.sprite.Sprite):
id_iter = itertools.count()
def __init__(self, maturingSpeed, x, y):
super(Amoeba, self).__init__()
self.id = 'amoeba' + str(next(Amoeba.id_iter))
idList.append(self.id)
self.surf = pygame.Surface((10,10))
if maturingSpeed <= 0:
maturingSpeed = 1
elif maturingSpeed >= 255:
maturingSpeed = 254
self.surf.fill((maturingSpeed, 0, 0))
self.rect = self.surf.get_rect(
center=(
x,
y,
)
)
self.speed = 2
self.age = 1
self.maturingSpeed = int(maturingSpeed)
self.life = 20000
def update(self):
if self.rect.left <= 0:
direction = 1
elif self.rect.right >= SCREEN_WIDTH:
direction = 2
elif self.rect.top <= 0:
direction = 3
elif self.rect.bottom >= SCREEN_HEIGHT:
direction = 4
else:
direction = random.randint(1, 4)
if direction == 1:
self.rect.move_ip(self.speed, 0)
elif direction == 2:
self.rect.move_ip(-self.speed, 0)
elif direction == 3:
self.rect.move_ip(0, self.speed)
elif direction == 4:
self.rect.move_ip(0, -self.speed)
self.life = self.life - 1
if self.life == 0:
self.kill()
modMaturingSpeed = self.maturingSpeed / 124
self.age = self.age + 1 * modMaturingSpeed
def collide(self):
global posList
posList = [[amoeba.rect.left, amoeba.rect.bottom] for amoeba in amoebas]
length = len(posList)
for i in range(length):
for amoeba in amoebas:
if amoeba.id == str(idList[i]):
ageOne = getattr(amoeba, 'age')
for h in range(i+1, length):
for amoeba in amoebas:
if amoeba.id == str(idList[h]):
ageTwo = getattr(amoeba, 'age')
OneX = int(posList[i][0])
OneY = int(posList[i][1])
TwoX = int(posList[h][0])
TwoY = int(posList[h][1])
if ageOne >= 100 and ageTwo >= 100:
if (OneX < TwoX + 10 and OneX + 10 > TwoX
and OneY < TwoY + 10 and 10 + OneY > TwoY):
for amoeba in amoebas:
if amoeba.id == str(idList[i]):
setattr(amoeba, 'age', 1)
pOMSinitial = int(getattr(amoeba, 'maturingSpeed'))
for amoeba in amoebas:
if amoeba.id == str(idList[h]):
setattr(amoeba, 'age', 1)
pTMSinitial = int(getattr(amoeba, 'maturingSpeed'))
locationX = OneX + random.randint(-10, 10)
locationY = OneY + random.randint(-10, 10)
if pOMSinitial >= pTMSinitial:
pOMSfinal = pOMSinitial + mutationConstant
pTMSfinal = pTMSinitial - mutationConstant
newMaturingSpeed = random.randint(pTMSfinal, pOMSfinal)
print(newMaturingSpeed)
else:
pOMSfinal = pOMSinitial - mutationConstant
pTMSfinal = pTMSinitial + mutationConstant
newMaturingSpeed = random.randint(pOMSfinal, pTMSfinal)
print(newMaturingSpeed)
amoebaname = Amoeba(newMaturingSpeed, locationX, locationY)
amoebas.add(amoebaname)
all_sprites.add(amoebaname)
screen.fill((255, 255, 255))
for i in range(5):
amoebaname = Amoeba(random.randint(100, 150), random.randint(0, SCREEN_WIDTH), random.randint(0, SCREEN_HEIGHT))
amoebas.add(amoebaname)
all_sprites.add(amoebaname)
p = 0
while True:
ageArray = [amoeba.age for amoeba in amoebas]
if p == 1000:
print(amoebas)
p = 0
else:
p = p + 1
time.sleep(0.00001)
screen.fill((255, 255, 255))
for event in pygame.event.get():
if event.type == QUIT:
break
amoebas.update()
a = Amoeba(1, 1, 1)
a.collide()
for entity in all_sprites:
screen.blit(entity.surf, entity.rect)
pygame.display.flip()
pygame.quit()
对不起,它比较长。程序中的一切工作正常,除了后代似乎由于某种原因没有繁殖,这意味着一旦原件死亡,什么都不会发生。
我的问题如此含糊的原因是我真的不明白问题可能是什么 - 原始变形虫的类与后代的类相同,并且程序没有抛出任何错误消息。
作者:黑洞官方问答小能手
链接:https://www.pythonheidong.com/blog/article/1847018/2a57ba2e97895317818c/
来源:python黑洞网
任何形式的转载都请注明出处,如有侵权 一经发现 必将追究其法律责任
昵称:
评论内容:(最多支持255个字符)
---无人问津也好,技不如人也罢,你都要试着安静下来,去做自己该做的事,而不是让内心的烦躁、焦虑,坏掉你本来就不多的热情和定力
Copyright © 2018-2021 python黑洞网 All Rights Reserved 版权所有,并保留所有权利。 京ICP备18063182号-1
投诉与举报,广告合作请联系vgs_info@163.com或QQ3083709327
免责声明:网站文章均由用户上传,仅供读者学习交流使用,禁止用做商业用途。若文章涉及色情,反动,侵权等违法信息,请向我们举报,一经核实我们会立即删除!