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发布于2021-02-27 15:11 阅读(279) 评论(0) 点赞(5) 收藏(0)
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学生类
类属性:学号、姓名、年龄、性别、成绩
班级类
属性:班级名称、班级中的学生[使用列表存储学生]
类方法:
1.查看该班级中的所有学生信息
2.查看指定学号的学生信息
3.查看班级中成绩不及格的学生信息
4.将班级中的学生按成绩降序排序
class Students(object):
def __init__(self, s_id, s_name, age, gander, scores):
self.id = s_id
self.name = s_name
self.age = age
self.gander = gander
self.scores = scores
def __str__(self):
return '学号:{},姓名:{},年龄:{},性别:{},成绩:{}'.format(self.id, self.name, self.age, self.gander, self.scores)
class Grade(object):
def __init__(self, c_name, student_list=None):
self.name = c_name
if student_list is None:
self.students = []
self.students = student_list
def show_all(self):
if self.students is None:
print('{}目前尚末开班...'.format(self.name))
return
for stu in self.students:
print(stu)
def get_id(self, num):
# result = filter(lambda s: s.id == num, self.students)
# for i in result:
# print(i)
for i in self.students:
if i.id == num:
return i
else:
return '未查询到相关学生信息...'
def get_failed(self):
result = filter(lambda s: s.scores < 60, self.students)
print('{}本次考核不合格同学如下:'.format(self.name))
coun = 0
for i in result:
print(i)
coun += 1
print('合计:{}个'.format(coun))
def order(self):
# 方法一
self.students.sort(key=lambda s: s.scores, reverse=True)
for i in self.students:
print(i)
# 方法二
print('#' * 40)
sorted(self.students, key=lambda s: s.scores, reverse=True)
s1 = Students('001', 'ZhangSan', 20, '男', 98)
s2 = Students('002', 'HanMeiMei', '18', '女', 99)
s3 = Students('003', 'ErMao', '18', '女', 49)
s4 = Students('004', 'Tom', '18', '男', 59)
c1 = Grade('一(1)班', [s1, s2, s3, s4])
c1.show_all()
c1.get_failed()
c1.order()
print(c1.get_id('003'))
原文链接:https://blog.csdn.net/weixin_44602192/article/details/114001512
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作者:898shd
链接: https://www.pythonheidong.com/blog/article/860097/7f4309a3c8fcd559c719/
来源: python黑洞网
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