它不会给用户 3 次机会，而是只打印 3 次“拒绝访问”，但我不知道如何更改代码，以便给用户 3 次机会，并且即使用户输入了错误的详细信息，它也会打印“欢迎”，所以如果有人能帮助我，我将不胜感激

老实说，我是个新手程序员，所以我并不指望它能起作用，但如果它真的起作用了，我会期望它给用户 3 次机会，如果他们都选错了，那么它会打印出类似“帐户被锁定”的内容

username = "Student1"
password = "WatfordLenMein"
input1 = input("Enter username: ")
input2 = input("Enter password: ")
for i in range(3):
    if username == input1 and password == input2:
        break
    else:
        print("Access denied")
print("Welcome")

解决方案

你的代码应该看起来像这样：

username = "Student1"
password = "WatfordLenMein"

is_login_successful = False

for i in range(3):
    # ask the user to enter login/password on every iteration of the loop.
    # if you keep this outside, then the user will be prompted to enter
    # credentials only once .. which is not what you want.
    input1 = input("Enter username: ")
    input2 = input("Enter password: ")

    # if the login/password match, then the loop is over
    if username == input1 and password == input2:
        is_login_successful = True
        break
    else:
        print("Access denied")

# as suggested by kuro, the use of a flag simplifies the overall logic
if (not is_login_successful):
    print("Account locked out")
    exit(1)

print("Welcome")
...